0.01q^2=4.7q

Solution for 0.01q^2=4.7q equation:

0.01q^2=4.7q

We move all terms to the left:

0.01q^2-(4.7q)=0

We add all the numbers together, and all the variables

0.01q^2-(+4.7q)=0

We get rid of parentheses

0.01q^2-4.7q=0

a = 0.01; b = -4.7; c = 0;
Δ = b2-4ac
Δ = -4.72-4·0.01·0
Δ = 22.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.7)-\sqrt{22.09}}{2*0.01}=\frac{4.7-\sqrt{22.09}}{0.02}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.7)+\sqrt{22.09}}{2*0.01}=\frac{4.7+\sqrt{22.09}}{0.02}
$